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Synopsis:
    #include <malloc.h>
    size_t _memavl( void );

Description:
    The _memavl function returns the number of bytes of memory available for
    dynamic memory allocation in the near heap (the default data segment).
     In the tiny, small and medium memory models, the default data segment
    is only extended as needed to satisfy requests for memory allocation.
     Therefore, you will need to call  _nheapgrow in these memory models
    before calling _memavl in order to get a meaningful result.

    The number returned by _memavl may not represent a single contiguous
    block of memory.  Use the  _memmax function to find the largest
    contiguous block of memory that can be allocated.

Returns:
    The _memavl function returns the number of bytes of memory available for
    dynamic memory allocation in the near heap (the default data segment).

See Also:
    calloc Functions Functions, _freect, _memmax, _heapgrow Functions Functions, malloc Functions
    Functions, realloc Functions Functions

Example:
    #include <stdio.h>
    #include <malloc.h>

    void main()
      {
        char *p;
        char *fmt = "Memory available = %u\n";

        printf( fmt, _memavl() );
        _nheapgrow();
        printf( fmt, _memavl() );
        p = (char *) malloc( 2000 );
        printf( fmt, _memavl() );
      }

    produces the following:

    Memory available = 0
    Memory available = 62732
    Memory available = 60730

Classification:
    WATCOM

Systems:
    All