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Synopsis:
    #include <i86.h>
    void intr( int inter_no, union REGPACK *regs );

Description:
    The intr function causes the computer's central processor (CPU) to be
    interrupted with an interrupt whose number is given by inter_no.  Before
    the interrupt, the CPU registers are loaded from the structure located
    by regs.  All of the segment registers must contain valid values.
     Failure to do so will cause a segment violation when running in protect
    mode.  If you don't care about a particular segment register, then it
    can be set to 0 which will not cause a segment violation.  Following the
    interrupt, the structure located by regs is filled with the contents of
    the CPU registers.

    This function is similar to the  int86x function, except that only one
    structure is used for the register values and that the BP (EBP in 386
    library) register is included in the set of registers that are passed
    and saved.

    You should consult the technical documentation for the computer that you
    are using to determine the expected register contents before and after
    the interrupt in question.

Returns:
    The function does not return a value.

See Also:
    bdos, int386, int386x, int86, int86x, intdos, intdosx, segread

Example:
    #include <stdio.h>
    #include <string.h>
    #include <i86.h>

    void main() /* Print location of Break Key Vector */
      {
        union REGPACK regs;

        memset( &regs, 0, sizeof(union REGPACK) );
        regs.w.ax = 0x3523;
        intr( 0x21, &regs );
        printf( "Break Key vector is "
    #if defined(__386__)
                "%x:%lx\n", regs.w.es, regs.x.ebx );
    #else
                "%x:%x\n", regs.w.es, regs.x.bx );
    #endif
      }

    produces the following:

    Break Key vector is eef:13c

Classification:
    Intel

Systems:
    DOS, Win, QNX, DOS/PM